Can You Write A Java Program To Check Whether The Given Number Is An Amstrong Number Or Not?

An Armstrong number is an integer whose sum of the cubes of each digits is same to the original number. Such as 371:
3^3+7^3+1^3=371

Following is the java code to check whether the given number is Armstrong or not

import java.io.Buffered Reader; //don't leave the gap
import java.io.IO Exception;//don't leave the gap
import java.io.Input StreamReader; //don't leave the gap

public class ArmstrongNumber
{

public static void main ( String[] a )
{
int a , value = 0 , c ,b = 0;
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

c = value;
System.out.print("Enter Number: ");
try
{
String str = br.readLine();
c = new Integer(str).intValue();
while (c != 0)
{
a = c % 10;
b = (a *a  a) + b;
c = c / 10;
}
if ( b == value )
System.out.print("given number is Armstrong number");
else
System.out.print("given number is not Armstrong number");

} catch (IOException e)
{
System.out.println(e);
}

}
}

Hope the above code will help you
Enjoy blurting :)

Import  java.util.Scanner;
class Num
{
public static void main(String args[])
{
int I,,j,sum,n;
Scanner in=new Scanner(System.in);
System.out.println("Enter number:");
n=in.nextInt();
while(n>0)
{
I=n%10;
sum=sum+I*I*I;
n=n/10;
}
if(sum==n)
System.out.println("number is amstrong");
else
System.out.println("number is not amstrong");
}
}

No